How do you solve $\frac { 1} { 2} ( x + 10) = \frac { 3} { 4} ( x + 20)$ ?

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Answer 1 · 2018-07-15T13:37:36

$x=-40$

Multiplying the given equation by $4$

$2(x+10)=3(x+20)$
expanding

$2x+20=3x+60$
subtracting $2x$ and $60$
we get
$x=-40$

Answer 2 · 2018-07-15T15:47:42

$x=-40$

We can multiply both sides of this equation by $4$ , since this is the LCM of the denominators. We now have

$2(x+10)=3(x+20)$

We can distribute the $2$ on the left and the $3$ on the right to get

$2x+20=3x+60$

Subtracting $3x$ from both sides gives us

$-x+20=60$

Subtracting $20$ from both sides, we get

$-x=40$

We can divide both sides by $-1$ to isolate $x$ . We get

$x=-40$

Hope this helps!

How do you solve \frac { 1} { 2} ( x + 10) = \frac { 3} { 4} ( x + 20)\frac { 1} { 2} ( x + 10) = \frac { 3} { 4} ( x + 20)?