How do you solve the system of equations $3x + 3y = - 3$ and $- 2x + 2y = 6$ ?

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Answer 1 · 2018-07-15T18:13:55

$x=-2,y=1$

Dividing the first equation by $3$ and the second one by $2$ we get the System

$x+y=-1$
$-x+y=3$
adding both we obtain

$2y=2$ so $y=1$

and

$x+1=-1$
so

$x=-2$

How do you solve the system of equations 3x + 3y = - 33x + 3y = - 3 and - 2x + 2y = 6- 2x + 2y = 6?