How do you simplify $\sqrt{15 x^{8} y^{3}}$ $sqrt(15x ^ { 8} y ^ { 3})$ ?

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Answer 1 · 2018-07-16T07:41:41

$x^{4} \cdot y \cdot \sqrt{15 y}$ $x^4*y*sqrt(15y)$

Using that $\sqrt{a b} = \sqrt{a} \sqrt{b}$ $sqrt(ab)=sqrt(a)sqrt(b)$ when ever $a \geq 0, b \geq 0$ $a>=0,b>=0$

$\sqrt{x^{8} y^{2} \cdot 15 y} = x^{4} y \sqrt{15 y}$ $sqrt(x^8y^2*15y)=x^4ysqrt(15y)$

How do you simplify √15x8y3sqrt(15x ^ { 8} y ^ { 3})?