How do you simplify $sqrt(49x^12y^4z^8)$ ?

Question

2676 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-16T07:48:02

$7x^6y^2z^4$

$sqrt(49x^12y^4z^8)=sqrt((7x^6y^2z^4)^2)=7x^6y^2z^4$

Answer 2 · 2018-07-16T07:49:25

$sqrt(49x^12y^4z^8) = 7x^6y^2z^4$

Find the square root of each factor.

Divide the indices by $2$

$sqrt(49x^12y^4z^8) = 7x^6y^2z^4$

Only the principal (positive) root is required.

How do you simplify sqrt(49x^12y^4z^8)sqrt(49x^12y^4z^8)?