How do you simplify $\sqrt{49 x^{12} y^{4} z^{8}}$ $sqrt(49x^12y^4z^8)$ ?

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Answer 1 · 2018-07-16T07:48:02

$7 x^{6} y^{2} z^{4}$ $7x^6y^2z^4$

$\sqrt{49 x^{12} y^{4} z^{8}} = \sqrt{{(7 x^{6} y^{2} z^{4})}^{2}} = 7 x^{6} y^{2} z^{4}$ $sqrt(49x^12y^4z^8)=sqrt((7x^6y^2z^4)^2)=7x^6y^2z^4$

Answer 2 · 2018-07-16T07:49:25

$\sqrt{49 x^{12} y^{4} z^{8}} = 7 x^{6} y^{2} z^{4}$ $sqrt(49x^12y^4z^8) = 7x^6y^2z^4$

Find the square root of each factor.

Divide the indices by $2$ $2$

$\sqrt{49 x^{12} y^{4} z^{8}} = 7 x^{6} y^{2} z^{4}$ $sqrt(49x^12y^4z^8) = 7x^6y^2z^4$

Only the principal (positive) root is required.

How do you simplify √49x12y4z8sqrt(49x^12y^4z^8)?