How do you solve the system of inequalities $3 x - 4 y \leq 12$ $3x-4y<=12$ and $- 2 x + 5 y \geq 10$ $-2x+5y>=10$ ?

Question

2046 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-16T12:05:51

$y>=min(2+2/5x,-3+3/4x)$

Solving the first inequality for $y$

subtracting $3x$ we get

$-4y<=12-3x$

dividing by $-4$

$y>=-3+3/4x$
solving the second inequality for $y$

adding $2x$

$5y>= 10+2x$

dividing by $5$

$y>=2+2/5x$
so

$y>=2+2/5x$

and

$y>=min(2+2/5x,-3+3/4x)$

How do you solve the system of inequalities 3x-4y<=123x−4y≤123x-4y<=12 and -2x+5y>=10−2x+5y≥10-2x+5y>=10?