How do you solve $1/2(x-4)-(5+x) = 0$ ?

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Answer 1 · 2018-07-16T12:10:57

$x=-14$

Multilying the given equation by $2$

$x-4-2(5+x)=0$
expanding

$x-4-10-2x=0$

combining like terms

$-14-x=0$

adding $x$

so we get

$x=-14$

How do you solve 1/2(x-4)-(5+x) = 01/2(x-4)-(5+x) = 0?