How do you solve the system of equations $a + 5 b = 1$ $a+ 5b = 1$ and $2 a = - 10 b + 2$ $2a = - 10b + 2$ ?

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Answer 1 · 2018-07-16T12:20:48

$- 5 b + 1, b$ $-5b+1,b$ where $b$ $b$ is a real number

Dividing the second equation by $2$ $2$ we get

$a = - 5 b + 1$ $a=-5b+1$

this is the same equation like the first one,
So we get all Solutions as

$- 5 b + 1, b$ $-5b+1,b$
where $b$ $b$ is a real number

How do you solve the system of equations a+5b=1a+ 5b = 1 and 2a=−10b+22a = - 10b + 2?