Question

The value of `x` satisfying the equation?

`1/log_3(1994)+1/log_6(1994)+1/log_9(1994)+1/log_12(1994)=1/(log_(3x)(1994))`

Answer 1

`1/log_3(1994)+1/log_6(1994)+1/log_9(1994)+1/log_12(1994)=1/(log_(3x)(1994))`

`=>log_(1994)3+log_(1994)6+log_(1994)9+log_(1994)12=log_(1994)(3x)`

`=>log_(1994)(3xx6xx9xx12)=log_(1994)(3x)`

`=>3x=3xx6xx9xx12`

`=>x=648`