Question

How would you write the formula of the conjugate base of the Bronstead-Lowry acids H2SO3 and HI?

Answer 1

for `H_2SO_3`: the conjugate base is `HSO_3^-`

for `HI`: the conjugate base is `I^-`

Explanation:

Given: Bronstead-Lowry acids `H_2SO_3` and `HI`

Bronstead-Lowry acid, base equation:

`B + HA iff HB^+ + A^-`

where `B`: base proton receiver; `" "HA` is the acid proton donor;

`HB^+` is the conjugate acid; `" "A^-` is the conjugate base

For sulfurous acid `(H_2SO_3)`:

`H_2SO_3 (aq) + H_2O (l) iff H_3O^+ (aq) + HSO_3^- (aq)`

the conjugate base is `HSO_3^-`

For hydroiodic acid `(HI)`:

`HI (aq) + H_2O (l) iff H_3O^+ (aq) + I^- (aq)`

the conjugate base is `I^-`