How do you find the amplitude, period and phase shift for y=cos3(theta-45^circ)+1/2?

1 Answer
Jul 17, 2018

As below.

Explanation:

Standard cosine function is y = A cos (Bx - C) + D

Given y = cos (3 theta - 135^@) + 1/2

A = 1, B = 3, C = 135^@ = (3pi)/4, D = 1/2

Amplitude = |A| = 1

Period = (2pi)/|B| = (2 pi) / 3

Phase Shift = -C / B = -((3pi)/4) / 3 = -pi/4, color(red)(pi/4) to the LEFT.

Vertical Shift = D = 1/2