How do you evaluate $(1 + 3 i) - (5 + 9 i)$ $(1+ 3i ) - ( 5+ 9i )$ ?

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Answer 1 · 2018-07-17T14:58:38

$- 4 - 6 i$ $-4-6i$

1) Remove brackets:
$1 + 3 i - 5 - 9 i$ $1+3i-5-9i$

2) Add real numbers to real numbers and complex numbers to complex numbers:
$- 4 - 6 i$ $-4-6i$

Answer 2 · 2018-07-17T14:59:15

$- 4 - 6 i$ $-4-6i$

Just separate real & imaginary parts & add/subtract them as follows

$(1 + 3 i) - (5 + 9 i)$ $(1+3i)-(5+9i)$

$= 1 + 3 i - 5 - 9 i$ $=1+3i-5-9i$

$= 1 - 5 + 3 i - 9 i$ $=1-5+3i-9i$

$= - 4 - 6 i$ $=-4-6i$

How do you evaluate (1+3i)−(5+9i)(1+ 3i ) - ( 5+ 9i )?