How do I evaluate #sqrt(x+10)=1/sqrt(x)+10# to find its real solution(s)?

1 Answer
Sonnhard
Jul 17, 2018

#xapprox 90.090492759#

Explanation:

We have #x>0# and we can sqauare the equation:
#x-1/x-90=20/sqrt(x)#

after squaring again and combinig like Terms we get

#x^4-180x^3+8098x^2-220x+1=0#
by a numerical method we get #xapprox 90,09492749#

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