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Between which two consecutive integers is 80 to the negative square root?

1 Answer

Shwetank Mauria

Jul 19, 2018

Between $- 9$ $-9$ and $- 8$ $-8$

Explanation:

$80$ $80$ lies between $8^{2} = 64$ $8^2=64$ and $9^{2} = 81$ $9^2=81$

Hence $\sqrt{80}$ $sqrt80$ lies between $8$ $8$ and $9$ $9$

However, we ave both $8^{2} = 64 = {(- 8)}^{2}$ $8^2=64=(-8)^2$ and $9^{2} = 81 = {(- 9)}^{2}$ $9^2=81=(-9)^2$

and hence $80$ $80$ to the negative square root

will lie between $- 9$ $-9$ and $- 8$ $-8$

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