How do you solve x-2y=-25 and 3x-y=0? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Shwetank Mauria Jul 19, 2018 #x=5# and #y=15# Explanation: As #3x-y=0#, we have #y=3x# hence #x-2y=-25# becomes #x-2*3x=-25# or #x-6x=-25# or #-5x=-25# i.e. #x=(-25)/(-5)=25/5=5# and #y=3*5=15# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 4008 views around the world You can reuse this answer Creative Commons License