How many grams of carbon are present in 10g of CH4?

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How many grams of carbon are present in 10g of CH4?

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Answer 1 · 2018-07-20T01:26:25

The molar mass of ${CH}_{4}$ $"CH"_4$ will be needed:

$M_{m} = 12.011 g/mol C + 4 \cdot 1.0079 g/mol H$ $M_m = "12.011 g/mol C" + 4 cdot "1.0079 g/mol H"$

$=$ $=$ $16.0426 g/mol$ $"16.0426 g/mol"$

The molar mass of $C$ $"C"$ is $12.011 g/mol$ $"12.011 g/mol"$ , so it makes up ${CH}_{4}$ $"CH"_4$ as:

$\frac{12.011}{16.0426} \times 100 % = 74.87 %$ $12.011/16.0426 xx 100% = 74.87%$ by mass

Because percent by mass is relative, we can choose any quantity of particles in setting up this ratio. I chose $1 mol$ $"1 mol"$ of ${CH}_{4}$ $"CH"_4$ , so that it has $1 mol C$ $"1 mol C"$ .

Therefore, $16.0426 g$ $"16.0426 g"$ of ${CH}_{4}$ $"CH"_4$ would have $12.011 g C$ $"12.011 g C"$ , and so, in ${10 g CH}_{4}$ $"10 g CH"_4$ , there would be

$0.7487 \times {10 g CH}_{4} = 7.487 g C$ $0.7487 xx "10 g CH"_4 = color(blue)("7.487 g C")$

If you found that there was $13.357 g$ $"13.357 g"$ of $C$ $"C"$ , it would not make physical sense. Why?

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How many grams of carbon are present in 10g of CH4?

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