Question

How do you solve for `log_4 x = -2`?

Answer 1

`x=1/16`

Explanation:

From the definition of logarithm, if `log_ab=c` then `b=a^c`

Hence as `log_4x=-2`,

we have `4^(-2)=x`

i.e `x=4^(-2)=1/4^2=1/16`