How do you factor #36a^2x - b^2#?

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Answer 1 · 2018-07-21T14:43:25

This can't be factorized further, but assuming...

It was given as below;

#36a^2 - b^2#

Then it can be factorized as;

#(6a + b) (6a - b)#

#36a^2 - b^2#

Rewriting as;

#6^2a^2 - b^2#

Using indices rule;

#x^2y^2 = (xy)^2#

Hence;

#(6a)^2 - b^2#

Recall, difference of two squares: #x^2 - y^2 = (x + y) (x - y)#

#(6a + b) (6a - b)#