How do you multiply $(3 k + 3) (2 k^{2} + 4 k + 2)$ $(3k + 3) ( 2k ^ { 2} + 4k + 2)$ ?

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Answer 1 · 2018-07-23T06:06:55

$6 k^{3} + 18 k^{2} + 18 k + 6$ $6k^3 +18k^2+18k+6$

$(3 k + 3) (2 k^{2} + 4 k + 2)$ $(3k+3)(2k^2+4k+2)$

Multiply each term in $(2 k^{2} + 4 k + 2)$ $(2k^2+4k+2)$ with $3 k$ $3k$ .

Then multiply each term in $(2 k^{2} + 4 k + 2)$ $(2k^2+4k+2)$ with $3$ $3$ .

$6 k^{3} + 12 k^{2} + 6 k + 6 k^{2} + 12 k + 6$ $6k^3+12k^2+6k+6k^2+12k+6$

$6 k^{3} + 18 k^{2} + 18 k + 6$ $6k^3 +18k^2+18k+6$

How do you multiply (3k+3)(2k2+4k+2)(3k + 3) ( 2k ^ { 2} + 4k + 2)?