How do you simplify $sqrt(4x^2 + 9x^4 + 16)$ ?

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Answer 1 · 2018-07-24T14:32:10

$3x^2 + 2x + 4$

$sqrt(4x^2 + 9x^4 + 16)$

Exponent

$(4x^2 + 9x^4 + 16)^(1/2)$

Reducing;

$(2^2x^2 + 3^2x^4 + 4^2)^(1/2)$

$(2^2x^2 + 3^2x^(2(2)) + 4^2)^(1/2)$

Multiplication

Multiplying via by the exponent;

$(2^(2 xx 1/2) x^(2 xx 1/2) + 3^(2 xx 1/2)x^(2(2 xx 1/2)) + 4^(2 xx 1/2))$

Simplifying;

$2^1 x^1 + 3^1x^(2(1)) + 4^(1)$

$2x + 3x^2 + 4$

Rearranging;

$3x^2 + 2x + 4 -> "Simplified"$

How do you simplify sqrt(4x^2 + 9x^4 + 16)sqrt(4x^2 + 9x^4 + 16)?