How do you divide #(- 2v ^ { 3} + 10v ^ { 2} - 27) \div ( v - 4)#?

1 Answer
Guillaume L.
Jul 24, 2018

#(-2v^3+10v^2-27)/(v-4)=-2v^2+2v+8+5/(v-4)#

Explanation:

#(-2v^3+10v^2-27)/(v-4)#

#=(-2v^2(v-4)+2v^2-27)/(v-4)#

#=(-2v^2(v-4)+2v(v-4)+8v-27)/(v-4)#

#=(-2v^2(v-4)+2v(v-4)+8(v-4)+5)/(v-4)#

#=-2v^2+2v+8+5/(v-4)#

\0/ here's our answer !

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