How do you solve $9 (8 t + 1) - 16 = t - (t + 6)$ $9( 8t + 1) - 16= t - ( t + 6)$ ?

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Answer 1 · 2018-07-25T00:31:11

$t = \frac{1}{72}$ $color(indigo)(t = 1 / 72$

$9 (8 t + 1) - 16 = t - (t + 6)$ $9(8t + 1) - 16 = t - (t + 6)$

$\Rightarrow 72 t + 9 - 16 = t - t - 6$ $=> 72t + 9 - 16 = t - t -6$ , removing braces.

$=> 72t -cancel t +cancel t = -9 + 16 - 6$ , bringing like terms together.

$72t = 1$ , simplifying.

$color(indigo)(t = 1 / 72$

Answer 2 · 2018-07-25T00:33:25

$t = 1/72$

$9(8t+1) - 16 = t - (t+6)$

Simplify both sides by distributing:
$72t + 9 - 16 = t - t - 6$

Combine like terms:
$72t - 7 = -6$

Add $color(blue)7$ to both sides:
$72t - 7 quadcolor(blue)(+quad7) = -6 quadcolor(blue)(+quad7)$

$72t = 1$

Divide both sides by $color(blue)(72)$ :
$(72t)/color(blue)72 = 1/color(blue)72$

Therefore,
$t = 1/72$

Hope this helps!

How do you solve 9( 8t + 1) - 16= t - ( t + 6)9(8t+1)−16=t−(t+6)9( 8t + 1) - 16= t - ( t + 6)?