How do you solve $3 {sec}^{2} x - 4 = 0$ $3sec^2x - 4=0$ ?

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How do you solve $3 {sec}^{2} x - 4 = 0$ $3sec^2x - 4=0$ ?

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Answer 1 · 2018-07-25T06:53:49

$x = \frac{π}{6}, \frac{5 π}{6}, \frac{7 π}{6}, \frac{11 π}{6}$ $x=pi/6,(5pi)/6,(7pi)/6,(11pi)/6$ in the domain $0 \leq x \leq 2 π$ $0 <=x <=2pi$

Explanation:

$3 {sec}^{2} x = - 4 = 0$ $3sec^2x=-4=0$
${sec}^{2} x = \frac{4}{3}$ $sec^2x=4/3$
$\frac{1}{{cos}^{2} x} = \frac{4}{3}$ $1/cos^2x=4/3$
${cos}^{2} x = \frac{3}{4}$ $cos^2x=3/4$
$cos x = \pm \frac{\sqrt{3}}{2}$ $cosx=+-sqrt3/2$
$x = \frac{π}{6}, π - \frac{π}{6}, π + \frac{π}{6}, 2 π - \frac{π}{6}$ $x=pi/6,pi-pi/6,pi+pi/6,2pi-pi/6$
$x = \frac{π}{6}, \frac{5 π}{6}, \frac{7 π}{6}, \frac{11 π}{6}$ $x=pi/6,(5pi)/6,(7pi)/6,(11pi)/6$ in the domain $0 \leq x \leq 2 π$ $0 <=x <=2pi$

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How do you solve $3 {sec}^{2} x - 4 = 0$ $3sec^2x - 4=0$ ?

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