What is the standard form of $y = (2 x + 7) (- 3 x - 3) - 4 x^{2} - 8 x$ $y=(2x+7)(-3x-3) -4x^2-8x$ ?

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What is the standard form of $y = (2 x + 7) (- 3 x - 3) - 4 x^{2} - 8 x$ $y=(2x+7)(-3x-3) -4x^2-8x$ ?

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Answer 1 · 2018-07-26T07:57:59

$y = - 10 x^{2} - 35 x - 21$ $y=-10x^2-35x-21$

Explanation:

Given -

$y = (2 x + 7) (- 3 x - 3) - 4 x^{2} - 8 x$ $y=(2x+7)(-3x-3)-4x^2-8x$

$y = - 6 x^{2} - 21 x - 6 x - 21 - 4 x^{2} - 8 x$ $y=-6x^2-21x-6x-21-4x^2-8x$

$y = - 10 x^{2} - 35 x - 21$ $y=-10x^2-35x-21$

Answer 2 · 2018-07-26T07:58:54

Expand the brackets

$y = (2 x + 7) (- 3 x - 3) - 4 x^{2} - 8 x$ $y=(2x+7)(-3x-3)-4x^2-8x$

$\Rightarrow y = - 6 x^{2} - 6 x - 21 x - 21 - 4 x^{2} - 8 x$ $=> y=-6x^2-6x-21x-21-4x^2-8x$

Collect like terms

$\Rightarrow y = - 10 x^{2} - 35 x - 21$ $=> y=-10x^2-35x-21$

Now it is in the form $y = a x^{2} + b x + c$ $y=ax^2+bx+c$

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What is the standard form of $y = (2 x + 7) (- 3 x - 3) - 4 x^{2} - 8 x$ $y=(2x+7)(-3x-3) -4x^2-8x$ ?

2 Answers

Explanation:

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Science

Math

Humanities

... and beyond

What is the standard form of y=(2x+7)(−3x−3)−4x2−8xy=(2x+7)(-3x-3) -4x^2-8x?

2 Answers

Explanation:

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Impact of this question

What is the standard form of $y = (2 x + 7) (- 3 x - 3) - 4 x^{2} - 8 x$ $y=(2x+7)(-3x-3) -4x^2-8x$ ?