How do you simplify $x - 1 - \frac{2}{x + 1}$ $x- 1- \frac { 2} { x + 1}$ ?

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Answer 1 · 2018-07-28T01:11:43

$\Rightarrow \frac{x^{2} - 3}{x + 1}$ $color(indigo)(=> (x^2 - 3) / (x + 1)$

$(x - 1) - (\frac{2}{x + 1})$ $(x - 1) - (2 / (x + 1))$

$\Rightarrow \frac{((x - 1) (x + 1)) - 2}{x = 1}, taking L CM as (x + 1)$ $=>(((x-1) (x + 1)) - 2) / (x = 1), " taking L CM as " (x + 1)$

$\Rightarrow \frac{x^{2} - 1 - 2}{x + 1}, Multiplying after removing brackets$ $=> (x^2 - 1 -2) / (x + 1), " Multiplying after removing brackets"$

$\Rightarrow \frac{x^{2} - 3}{x + 1}, simplifying$ $=> (x^2 - 3) / (x + 1), " simplifying"$

How do you simplify x−1−2x+1x- 1- \frac { 2} { x + 1}?