How do you graph the parabola $y = \frac{7}{4} x^{2}$ $y=7/4x^2$ using vertex, intercepts and additional points?

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Answer 1 · 2018-07-28T05:34:54

Vertex $(0, 0)$ $(0,0)$

Given -

$y = \frac{7}{4} x^{2}$ $y=7/4x^2$

The above function has no constant term. Hence its vertex is at the origin. It has no intercepts.

Vertex $(0, 0)$ $(0,0)$

Take a few points on either side of $(x = 0)$ $(x=0)$ . Find the corresponding Y values.

Plot them on a graph sheet. Join all the points with the help of a smooth curve.
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How do you graph the parabola y=74x2y=7/4x^2 using vertex, intercepts and additional points?