Question

How do you find the amplitude, period, phase shift for `y=sin2(x+(3pi)/4)`?

Answer 1

Please see the explanation below.

Explanation:

Compare this equation to

`y=asin(omegax+phi)`

Here,

`y=sin2(x+3/4pi)=sin(2x+3/2pi)`

The amplitude is `a=1`

The period is `T=2pi/2=pi`

The phase shift is `phi=3/2pi`

graph{sin(2x+3/2pi) [-7.02, 7.024, -3.51, 3.51]}