How do you solve #\frac { 1} { 4} ( 5x - 27) \leq \frac { x + 10} { 3} < 10#?

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Answer 1 · 2018-07-29T22:00:48

#x notin RR#

Let's focus on #1/4(5x-27)<=(x+10)/3#

#3(5x-27)=<4(x+10)#

#15x-81<=4x+40#

#11x<=121#

#x<=11#

But #x<=11<10#, so there's no solution for this equation.

\0/ here's our answer !