How do you solve $\frac { 1} { 4} ( 5x - 27) \leq \frac { x + 10} { 3} < 10$ ?

Question

1516 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-29T22:00:48

$x notin RR$

Let's focus on $1/4(5x-27)<=(x+10)/3$

$3(5x-27)=<4(x+10)$

$15x-81<=4x+40$

$11x<=121$

$x<=11$

But $x<=11<10$ , so there's no solution for this equation.

\0/ here's our answer !

How do you solve \frac { 1} { 4} ( 5x - 27) \leq \frac { x + 10} { 3} < 10\frac { 1} { 4} ( 5x - 27) \leq \frac { x + 10} { 3} < 10?