How do you graph #y<=(x+1)^3#?
1 Answer
Jul 30, 2018
Please see below.
Explanation:
The graph of
graph{(x+1)^3 [-10, 10, -5, 5]}
This divides Cartesian plane in three parts.
- The curve itself which satisfies
#y=(x+1)^3# and this is a part of solution as the desired graph#y<=(x+1)^3# includes equality. - Area to the left of it. One point
#(-5,0)# lies in this part and for this we have#0>(-5+1)^3# and hence this point does not lie on the graph. So will other points to the left of curve. - Area to the right of it. One point
#(0,0)# lies in this part and for which we have#0<(0+1)^3# and hence this point lies on the graph. So will other points to the right of the curve.
Hence solution is
graph{y<=(x+1)^3 [-10, 10, -5, 5]}
Note : If we had the inequality
graph{y<(x+1)^3 [-10, 10, -5, 5]}