How do you differentiate $y=ln(3xe^(1-x))$ ?

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Answer 1 · 2018-07-31T17:35:12

$(1-x)/x$ .

$y=ln(3xe^(1-x))$ .

Using the usual rules of log function, we have,

$y=ln3+lnx+lne^(1-x), or,$

$y=ln3+lnx+(1-x)lne=ln3+lnx+1-x$ .

$:. dy/dx=0+1/x+0-1$ .

$rArr dy/dx=(1-x)/x$ , as Respected Sonnhard has derived!

How do you differentiate y=ln(3xe^(1-x))y=ln(3xe^(1-x))?