Evaluate the six trigonometric functions (if possible) for the real number t = π?

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Evaluate the six trigonometric functions (if possible) for the real number t = π?

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Answer 1 · 2018-08-02T01:39:46

Hope this helps.

Explanation:

![https://socratic.org/questions/in-which-quadrants-do-cosine-and-tangent-have-the-opposite-sign](useruploads.socratic.org)

The six trigonometric functions are

$sin, csc, cos, sec, tan, cot$ $sin, csc, cos, sec, tan, cot$

$π is in second quadrant. Hence, only sin, csc are positive as per the chart above$ $pi " is in second quadrant. Hence, only " sin, csc " are positive as per the chart above"$

![https://tinycards.duolingo.com/decks/3GDzDtLQ/unit-circle-trig-functions](useruploads.socratic.org)

$sin t = sin π = sin 0 = 0$ $sin t = sin pi = sin 0 = 0$

$csc π = \frac{1}{sin π} = \frac{1}{0} = \infty$ $csc pi = 1/ sin pi = 1 / 0 = oo$

$cos t = cos π = - 1$ $cos t = cos pi = -1$

$sec π = \frac{1}{cos π} = \frac{1}{- 1} = - 1$ $sec pi = 1 / cos pi = 1 / -1 = -1$

$tan t = tan π = - \frac{0}{- 1} = 0$ $tan t = tan pi = -0/ -1 = 0$

$cot π = \frac{1}{tan π} = - \frac{1}{0} = - \infty$ $cot pi = 1/ tan pi = -1 / 0 = -oo$

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Evaluate the six trigonometric functions (if possible) for the real number t = π?

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