How do you simplify $\frac { 8y ^ { 6} } { 40y ^ { 2} }$ ?

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Answer 1 · 2018-08-02T02:07:00

$y^4/5$

We can rewrite this as

$8/40*y^6/y^2$

When we divide exponents of the same base, we subtract the exponents. Thus, this simplifies to

$y^4/5$

Hope this helps!

Answer 2 · 2018-08-02T02:26:28

$color(blue)(=> y^4 / 5$

$"According to theory of indices," a ^m / a^n = a^(m-n)$

$"Given " (8 y^6) / (40 y^2)$

$=> (cancel 8 y^6) / (cancel(40)^color(red)(5) y^2)$

$=> y^6 / (5 y^2)$

$=> (y^6 / y^2)/5 = (y^(6-2))/5$

$=> y^4/5$

How do you simplify \frac { 8y ^ { 6} } { 40y ^ { 2} }\frac { 8y ^ { 6} } { 40y ^ { 2} }?