What is the equation of the line passing through the points #(4, -5)# and #(2,-7)#?

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Answer 1 · 2018-08-02T10:01:27

#y=x-9#

First you need to find the gradient of the line

#m=(-5+7)/(4-2)=2/2=1#

Then, using the point gradient formula

#y-y_1=m(x-x_1)#
where #(x_1,y_1)# can be either point and #m# is the gradient

So, I'm using the point #(4,-5)#

#(y+5)=1(x-4)#

#y+5=x-4#

#y=x-9#