How do you solve #3p - 1 = 5(p -1) - 2(7- 2p)#?

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Answer 1 · 2018-08-02T11:58:25

By arranging the equation

#3p -1 = 5p - 5 - 14 + 4p#

after getting rid of parantheses.

Now collect p terms on the right-hand side and numbers on the other:

#-1 + 5 +14 = 5p + 4p - 3p#

#18 = 6 p#

#18/6 = p#

#3=p#

The answer is #p=3#

Answer 2 · 2018-08-02T12:39:17

#p = 3#

#3p - 1 = 5(p-1) - 2(7-2p)#

#3p - 1 = 5p - 5 - 14 + 4p#, Removing bracelets.

#3p - 5p - 4p = -5 - 14 + 1#, bringing like terms together.

#-6p = - 18#, simplifying.

#p = (-18) / (-6) = 3#

Answer 3 · 2018-08-02T23:48:19

#p=3#

We can distribute the parenthesis on the right to get

#3p-1=5p-5+4p-14#

We can combine our like terms on the right to get

#3p-1=9p-19#

Next, let's add #1# to both sides to get

#3p=9p-18#

Next, do get our variables on one side, let's subtract #9p# from both sides to get

#-6p=-18#

Lastly, we can divide both sides by #-6# to get

#p=3#

Hope this helps!