How do you divide and simplify $\frac { 9y ^ { 10} x ^ { 3} } { 11y ^ { 2} } \div \frac { 10y ^ { 6} x ^ { 4} } { 7x ^ { 3} }$ ?

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Answer 1 · 2018-08-03T10:07:34

$(63x^2y^2)/110$

$(9y^10x^3)/(11y^2)divide(10y^6x^4)/(7x^3)$

$=(9y^10x^3)/(11y^2)times(7x^3)/(10y^6x^4)$

$=(63x^6y^10)/(110x^4y^8)$

$=(63cancel(x^6)x^2cancel(y^10)y^2)/(110cancel(x^4y^8)$

$=(63x^2y^2)/110$

How do you divide and simplify \frac { 9y ^ { 10} x ^ { 3} } { 11y ^ { 2} } \div \frac { 10y ^ { 6} x ^ { 4} } { 7x ^ { 3} }\frac { 9y ^ { 10} x ^ { 3} } { 11y ^ { 2} } \div \frac { 10y ^ { 6} x ^ { 4} } { 7x ^ { 3} }?