How do I factor the problem completely?(6ax²-9x)

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Answer 1 · 2018-08-03T21:06:57

$3 x (2 a x - 3)$ $3x(2ax-3)$

We will check the solution by Expanding

$3 x (2 a x - 3) = 3 x \cdot 2 a x - 6 x = 6 a x^{2} - 9 x$ $3x(2ax-3)=3x*2ax-6x=6ax^2-9x$

Answer 2 · 2018-08-03T22:55:42

$3 x (2 a x - 3)$ $3x(2ax-3)$

Both terms have an $3 x$ $3x$ in common, so we can factor that out, and we get

$3 x (2 a x - 3)$ $3x(2ax-3)$

Since we can't factor the binomial in the parenthesis any further, we are done.

Hope this helps!