What is the negative root of the equation #abs(2x+3)=11#?

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Answer 1 · 2018-04-27T05:32:28

# -7#.

# |2x+3|=11#.

#:. 2x+3=+-11#.

#2x+3=+11 rArr 2x=11-3=8 rArr x=4 gt 0#.

If, #2x+3=-11," then, "2x=-14," giving, "x=-7 lt 0#.

#:. x=-7#, is the desired root!

Answer 2 · 2018-08-04T00:41:53

#x=-7#

This equation can be interpreted as

#2x+3=11# and #2x+3=-11#, but we are concerned with only the negative root, as the question says.

We have

#2x+3=-11#

We can subtract #3# from both sides to get

#2x=-14#

Lastly, we can divide both sides by #2# to isolate #x#. We get

#x=-7#

Hope this helps!