How do you factor the trinomial $8 x^{2} - 11 x + 3$ $8x^2 − 11x + 3$ ?

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How do you factor the trinomial $8 x^{2} - 11 x + 3$ $8x^2 − 11x + 3$ ?

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Answer 1 · 2018-08-04T01:08:38

$8 x^{2} - 11 x + 3 = (x - 1) (8 x - 3)$ $8x^2-11x+3=(x-1)(8x-3)$

Explanation:

$8 x^{2} - 11 x + 3$ $8x^2-11x+3$

$= 8 x^{2} - 8 x - 3 x + 3$ $=8x^2-8x-3x+3$

$= 8 x (x - 1) - 3 (x - 1)$ $=8x(x-1)-3(x-1)$

$= (x - 1) (8 x - 3)$ $=(x-1)(8x-3)$

Answer 2 · 2018-08-04T11:02:02

$(x - 1) (8 x - 3)$ $(x-1)(8x-3)$

Explanation:

$factor the quadratic using the a-c method$ $"factor the quadratic using the a-c method"$

$the factors of 8 \times 3 = 24$ $"the factors of "8xx3=24$

$which sum to - 11 are - 8 and - 3$ $"which sum to "-11" are "-8" and "-3$

$use these factors to split the middle term$ $"use these factors to split the middle term"$

$8 x^{2} - 8 x - 3 x + 3 \leftarrow factor by grouping$ $8x^2-8x-3x+3larrcolor(blue)"factor by grouping"$

$= 8 x (x - 1) - 3 (x - 1)$ $=color(red)(8x)(x-1)color(red)(-3)(x-1)$

$take out the common factor (x - 1)$ $"take out the "color(blue)"common factor "(x-1)$

$= (x - 1) (8 x - 3)$ $=(x-1)(color(red)(8x-3))$

$8 x^{2} - 11 x + 3 = (x - 1) (8 x - 3)$ $8x^2-11x+3=(x-1)(8x-3)$

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How do you factor the trinomial $8 x^{2} - 11 x + 3$ $8x^2 − 11x + 3$ ?

2 Answers

Explanation:

Explanation:

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How do you factor the trinomial $8 x^{2} - 11 x + 3$ $8x^2 − 11x + 3$ ?