How do you solve for x: #3|2x − 1| − 4 = 29#?

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Answer 1 · 2017-08-02T10:14:54

Solution : # x=6 or x = -5#

1) #3|2x-1|-4 = 29 or 3|2x-1| = 29+4 or |2x-1| = 33/3 # or

#|2x-1| = 11 or 2x -1 = 11 or 2x = 12 or x=6 # OR

2) #3|2x-1|-4 = 29 or 3|2x-1| = 29+4 or |2x-1| = 33/3 # or

#|2x-1| = 11 or 2x -1 = -11 or 2x = -10 or x= -5 #

Solution : # x=6 or x = -5# [Ans]

Answer 2 · 2018-08-04T01:14:51

#x=6# and #x=-5#

Let's start by adding #4# to both sides to get

#3|2x-1|=33#

Next, we can divide both sides by #3# to get

#|2x-1|=11#

We have two different scenarios:

#2x-1=11# and #2x-1=-11#

For both, we can add #1# to both sides to get

#2x=12# and #2x=-10#

Dividing both sides by #2#, we get

#x=6# and #x=-5#

Hope this helps!