How do you factor the trinomial #b^2 + 12b + 32#?

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Answer 1 · 2018-08-04T01:19:39

#(b + 4) (b + 8)#

#b^2 + 12b + 32#

Using Factorization Method..

The factors are;

#4 and 8#

#12b = 4b + 8b#

#32 = 4 xx 8#

Hence;

#b^2 + 4b + 8b + 32#

Grouping;

#(b^2 + 4b) (8b + 32)#

#b(b + 4) +8(b + 4)#

#(b + 4) (b + 8) -> "Factorized"#

Answer 2 · 2018-08-05T01:34:01

#(b+8)(b+4)#

Let's do a little thought experiment:

What two number sum up to #12# (middle term) and have a product of the last term #(32)#?

After some trial and error, we arrive at #8# and #4#. This means we can factor this business as

#(b+8)(b+4)#

Hope this helps!