The ratio of electric force betweem 2 electrons to the gravotational force between them is of the order of?

1 Answer

let the distance between them to be #r#

#F_g=(Gm_1m_2)/(r^2)#

#F_c=(Kq_1q_2)/r^2#

From a google search we find

#q_e=1.6*10^-19 C#
#m_e=9.1*10^-31 Kg#
#G=6.67*10^-11 m^3/(Kgs^2)#
#K=9*10^9 (Nm^2)/C^2#

#F_c/F_g=[Kq^2]/[Gm^2]##=(9*10^9*2.56*10^-38*10^11*10^62)/(6.67*82.81)#

#=0.0417*10^44# a very big number because electrons have extremly small mass