What is #Sin(arcsin(3/5)+(arctan-2))#?

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Answer 1 · 2018-08-04T16:17:09

#- 1/sqrt 5#

#sin ( arcsin ( 3/5 ) + arctan ( - 2 ) )#

#= sin ( arcsin ( 3/5 ) + arcsin ( -2/sqrt5 ) )#

#= (sin arcsin (3/5)) (cos arcsin(-2/sqrt5))#

#+ (cos arcsin (3/5))( sin arcsin(-2/sqrt5))#

#= 3/5 cos arccos ( 1/sqrt5 ) + cos arccos ( 4/5) ( -2/sqrt5)#

#= (3/5)( 1/sqrt5 ) - ( 4/5 ) ( 2/sqrt5 )#

#= - 1/sqrt5