How do you evaluate #5x+11\times 2=16x-26#?

2 Answers
Mar 27, 2017

#x=48/11#

Explanation:

First simplify the expression on each side of the equation

#5x+11*2=16x-26#

#5x + 22 = 16x-26#

Group like terms. When a term is moved to the other side of an equation, the sign changes.

#22+26=16x-5x#

#48=11x#

Divide both sides by 11 so that #x# stands alone

#(cancel(11)x)/cancel(11)=48/11#

#x=48/11#

Aug 5, 2018

#x=48/11#

Explanation:

This simplifies to

#5x+22=16x-26#

To make this easier, I'll switch the sides. I didn't do any math here, I only switched the sides:

#16x-26=5x+22#

We can add #26# to both sides to get

#16x=5x+48#

Next, to get our #x# terms on one side, let's subtract #5x# from both sides to get

#11x=48#

To completely isolate #x#, we can divide both sides by #11# to get

#x=48/11#

Hope this helps!