How do you solve #-3x - 12\leq 3x + 12#?

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Answer 1 · 2017-02-04T03:03:03

#x>=-4#

Solve #-3x-12<=3x+12#

Add #3x# to both sides and simplify.

#-12<=3x+12+3x#

#-12<=6x+12#

Subtract #12# from both sides and simplify.

#-12-12<=6x#

#-24<=6x#

Divide both sides by #6# and simplify.

#-24/6<=x#

#-4<=x#

Switch sides.

#x>=-4#

Answer 2 · 2018-08-06T02:57:28

#x>= -4#

We can start by adding #12# to both sides to get

#-3x<=3x+24#

Next, we can subtract #3x# from both sides to get

#-6x<=24#

Lastly, we can divide by #-6# on both sides. Since we are dividing by a negative, we must flip the inequality. We get

#x>= -4#

Hope this helps!