How do you write the equation $81^(1/2)=9$ into logarithmic form?

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Answer 1 · 2018-08-06T12:16:33

$color(indigo)(1/2 log 81 = log 9$

$81^(1/2) = 9$

Taking Log on both sides,

$log(81)^(1/2) = log 9$

$color(indigo)(1/2 log 81 = log 9$

$color(green)(1/2 log(9)^2 = log 9$

How do you write the equation 81^(1/2)=981^(1/2)=9 into logarithmic form?