What is the equation of the line between #(-20,2)# and #(-3,8)#?

Question

1385 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-08-06T13:13:50

#6x-17y+154=0#

Equation of a line joining two points #(x_1,y_1)# and #(x_2,y_2)# is

#(y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)#

Hence equation of line joining #(-20,2)# and #(-3,8)# is

#(y-2)/(8-2)=(x-(-20))/(-3-(-20))#

or #(y-2)/6=(x+20)/17#

or #17y-34=6x+120#

or #6x-17y+154=0#