State the units for intensity using only fundamental units? (Hint: work from $W/(m^2)$ )

Question

2239 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-08-06T21:50:55

$(kg)/(s^3)$

Steps shown below:

$W/m^2= (J/s)/m^2= ((Nm)/s)/m^2= (((kgm)/s^2*m)/s)/m^2= (((kgm^2)/s^2)/s)/(m^2)=(( kgm^2)/s^3)/(m^2)= (kg)/(s^3)$

Answer 2 · 2018-08-06T22:03:10

$(kg)/s^3$
kilograms over seconds cubed

$m^2$ is already in fundamental units, so let's work on $W$ (which stands for power)

$W=(Fd)/t$

The fundamental unit for distance is $m$ and for the time it's $s$

$F=ma$

The fundamental unit for mass is $kg$ and the unit for acceleration is $m/s^2$

So, we know that $((kg*(m/s^2)*m)/s)/m^2$

Simplifying we get $(kg)/s^3$

State the units for intensity using only fundamental units? (Hint: work from W/(m^2)W/(m^2))