How do you solve $y = x^{2} - 6 x - 1$ $y=x^2-6x-1$ using the quadratic formula?

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Answer 1 · 2018-08-07T08:55:46

$x = 3 \pm \sqrt{10}$ $x=3+-sqrt10$

$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $x=(-b+-sqrt(b^2-4ac))/(2a)$
where your quadratic equation is $y = a x^{2} + b x + c$ $y=ax^2+bx+c$

$x = \frac{6 \pm \sqrt{{(- 6)}^{2} - 4 (1) (- 1)}}{2 \times 1}$ $x=(6+-sqrt((-6)^2-4(1)(-1)))/(2times1)$

$x = \frac{6 \pm \sqrt{36 + 4}}{2}$ $x=(6+-sqrt(36+4))/2$

$x = \frac{6 \pm \sqrt{40}}{2}$ $x=(6+-sqrt40)/2$

$x = \frac{6 \pm 2 \sqrt{10}}{2}$ $x=(6+-2sqrt10)/2$

$x = 3 \pm \sqrt{10}$ $x=3+-sqrt10$

How do you solve y=x2−6x−1y=x^2-6x-1 using the quadratic formula?