How do you find the period and amplitude for $y= -4 sin((2x)/3)$ ?

Question

5059 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-08-08T01:02:41

$color(green)(Amplitude = 4, " Period " = 3pi$

Standard form of a sinusoidal function is $y = A sin (Bx - C) + D$

$"Given " y = -4 sin (2/3 x)$

$A = -4, B = 2/3, C = D = 0$

$Amplitude = |A| = |-4| = 4$

$"Period ' = (2pi) / |B| = (2pi) / (2/3) = 3 pi$

$"Phase Shift " = (-C/B) = 0$

$"Vertical Shift " = D = 0$

graph{-4 sin(2/3 x) [-10, 10, -5, 5]}

How do you find the period and amplitude for y= -4 sin((2x)/3)y= -4 sin((2x)/3)?