How much work would it take to push a $2 k g$ $2 kg$ weight up a $7 m$ $7 m$ plane that is at an incline of $\frac{5 π}{12}$ $(5pi) / 12$ ?

Question

1637 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-08-08T08:26:58

The work is $= 132.5 J$ $=132.5J$

The work done is equal to the potential energy gained.

The potential energy is

$P E = m g h = m g l sin θ$ $PE=mgh=mglsintheta$

The mass is $m = 2 k g$ $m=2kg$

The length of the plane is $l = 7 m$ $l=7m$

The angle is $θ = \frac{5}{12} π$ $theta=5/12pi$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Therefore,

$W = 2 \cdot 9.8 \cdot 7 \cdot sin (\frac{5}{12} π) = 132.5 J$ $W=2*9.8*7*sin(5/12pi)=132.5J$

How much work would it take to push a 2 kg 2kg 2 kg weight up a 7 m 7m 7 m plane that is at an incline of (5pi) / 12 5π12 (5pi) / 12 ?